CALCULUS!!!!!!!!!!!!!!!!!!!!

komett October 11, 2017 10:57 pm

anyone know how to do related rates?
https://imgur.com/a/8Iutg

i thought i knew what i was doing but uh turns out i was Wrong

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Responses

komett October 11, 2017 11:06 pm

also here is how i worked question a
https://imgur.com/a/3dYHh

blueastronomy18 October 11, 2017 11:31 pm

i think I know how to do this. Do you still need help?

komett October 11, 2017 11:36 pm

i think I know how to do this. Do you still need help? blueastronomy18

yes please

blueastronomy18 October 11, 2017 11:36 pm

Well...I'm just gonna try anyways...
y=tanx
dy/dt=sec^2(x)(dx/dt)
Since the problem gives you the value of dx/dt...
dy/dt=sec^2(x)(9)=9sec^2(x)
Then for a,b &c... all you have to do is plug in the number for x
Hope this is helpful.

komett October 11, 2017 11:43 pm

Well...I'm just gonna try anyways...y=tanxdy/dt=sec^2(x)(dx/dt)Since the problem gives you the value of dx/dt...dy/dt=sec^2(x)(9)=9sec^2(x)Then for a,b &c... all you have to do is plug in the number for xHo... blueastronomy18

thank you!!!! ε=ε=(ノ≧∇≦)ノ

blueastronomy18 October 11, 2017 11:44 pm

thank you!!!! ε=ε=(ノ≧∇≦)ノ komett

let me know if the answers are correct (=・ω・=)

komett October 11, 2017 11:45 pm

let me know if the answers are correct (=・ω・=) blueastronomy18

they are :D

blueastronomy18 October 11, 2017 11:49 pm

they are :D komett

ohhhh... thats good... good luck with cal

CALCULUS!!!!!!!!!!!!!!!!!!!!

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